例如：如下图所示，对数据库的EmailSource字段按日期分类汇总
因此我们可以写入如下的SQL语句类解决这样的问题
SELECT sum(case when `EmailSource`='FM' then 1 else 0 end) as FM_Statistic,sum(case when `EmailSource`='UOC' then 1 else 0 end) as UOC_Statistic,sum(case when `EmailSource`='OC' then 1 else 0 end) as OC_Statistic,DATE_FORMAT(Date,'%Y-%m-%d') AS `DateTime` FROM `user_performance` WHERE Email != '' AND Email != 'TOTAL'AND (DATE_FORMAT(Date,'%Y-%m-%d') >= DATE_FORMAT('2011-02-5','%Y-%m-%d')) AND (DATE_FORMAT(Date,'%Y-%m-%d') <= DATE_FORMAT('2011-03-07','%Y-%m-%d')) GROUP BY `Date` 搜索后结果为：
| 1 | 0 | 1 | 2011-02-07 |
| 2 | 0 | 2 | 2011-02-08 |
| 26 | 0 | 26 | 2011-02-09 |
| 26 | 0 | 26 | 2011-02-10 |
| 28 | 0 | 28 | 2011-02-11 |
| 31 | 0 | 31 | 2011-02-14 |
| 31 | 0 | 31 | 2011-02-15 |
| 30 | 0 | 30 | 2011-02-16 |
| 29 | 0 | 29 | 2011-02-17 |
| 28 | 0 | 28 | 2011-02-18 |
| 31 | 0 | 31 | 2011-02-21 |
| 32 | 0 | 32 | 2011-02-22 |
| 30 | 0 | 30 | 2011-02-23 |
| 32 | 0 | 32 | 2011-02-24 |
| 31 | 31 | 31 | 2011-02-25 |
| 4 | 4 | 4 | 2011-02-26 |
| 5 | 5 | 5 | 2011-02-27 |
| 29 | 29 | 29 | 2011-02-28 |
| 32 | 32 | 32 | 2011-03-01 |
| 30 | 30 | 30 | 2011-03-02 |